Answer
$\frac{3}{4(x-1)}$
Work Step by Step
We will use the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$ in the simplification of the fraction:
$\frac{9(x-1)^{2}}{12(x-1)^{3}}$
=$\frac{9(x-1)^{2-3}}{12}$
=$\frac{9(x-1)^{-1}}{12}$
=$\frac{3(x-1)^{-1}}{4}$
=$\frac{3}{4(x-1)}$
