Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.1 - Simplifying Algebraic Fractions - Problem Set 7.1 - Page 281: 29



Work Step by Step

We factor the expressions in both the numerator and denominator in order to cancel out common factors in the numerator and the denominator: $\frac{6x^{3}-15x^{2}y}{6x^{2}+24xy}$ =$\frac{3x(2x^{2}-5xy)}{3x(2x+8y)}$ =$\frac{(2x^{2}-5xy)}{(2x+8y)}$ =$\frac{x(2x-5y)}{2(x+4y)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.