Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.1 - Simplifying Algebraic Fractions - Problem Set 7.1: 11

Answer

$\frac{4xy}{9z}$

Work Step by Step

We use the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$ to help us cancel out common factors in the numerator and denominator: $\frac{32xy^{2}z^{3}}{72yz^{4}}$ =$\frac{32}{72}\times x\times\frac{y^{2}}{y}\times\frac{z^{3}}{z^{4}}$ =$\frac{4}{9}\times x\times y^{2-1}\times z^{3-4}$ =$\frac{4}{9}\times x\times y^{1}\times z^{-1}$ =$\frac{4}{9}\times x\times y^{1}\times \frac{1}{z^{1}}$ =$\frac{4xy}{9z}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.