## Elementary Algebra

Published by Cengage Learning

# Chapter 7 - Algebraic Fractions - 7.1 - Simplifying Algebraic Fractions - Problem Set 7.1 - Page 281: 10

#### Answer

$-\frac{8b}{13a^{2}}$

#### Work Step by Step

We use the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$ to help us cancel out common factors in the numerator and denominator: $\frac{-24a^{3}b^{3}}{39a^{5}b^{2}}$ =$\frac{-24}{39}\times\frac{a^{3}}{a^{5}}\times\frac{b^{3}}{b^{2}}$ =$\frac{-8}{13}\times a^{3-5}\times b^{3-2}$ =$-\frac{8}{13}\times a^{-2}\times b^{1}$ =$-\frac{8}{13}\times \frac{1}{a^{2}}\times b^{1}$ =$-\frac{8b}{13a^{2}}$

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