Answer
$5+0i$
Work Step by Step
First of all, recall that $i=\sqrt{-1}$, so $i^{2}=-1$
Also, since $(a+b)(a-b)=a^{2}-b^{2}$, we obtain:
$(-2-i)(-2+i)$
=$(-2)^{2}-(i)^{2}$
=$4-i^{2}$
=$4-(-1)$
=$4+1$
=$5$
Since we have to write the answer in the form $(a+bi)$, we write:
$5=5+0i$
