Answer
$-26+15i$
Work Step by Step
We multiply each term of the first complex number with the second complex number and then simplify:
$(-1-4i)(-2-7i)$
=$-1(-2-7i)-4i(-2-7i)$
=$2+7i+8i+28i^{2}$
=$2+15i+28(-1)$ [We substitute -1 in place of $i^{2}$ as $i^{2}=-1$]
=$2-28+15i$
=$-26+15i$
