Answer
$3-51i$
Work Step by Step
We multiply each term of the first complex number with the second complex number and then simplify:
$(9-3i)(2-5i)$
=$9(2-5i)-3i(2-5i)$
=$18-45i-6i+15i^{2}$
=$18-51i+15(-1)$ [We substitute -1 in place of $i^{2}$ as $i^{2}=-1$]
=$18-15-51i$
=$3-51i$
