Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.4 - Complex Numbers - Problem Set 11.4: 51

Answer

$61+0i$

Work Step by Step

First of all, recall that $i=\sqrt{-1}$, so $i^{2}=-1$ Also, since $(a+b)(a-b)=a^{2}-b^{2}$, we obtain: $(5-6i)(5+6i)$ =$(5)^{2}-(6i)^{2}$ =$25-36i^{2}$ =$25-36(-1)$ =$25+36$ =$61$ Since we have to write the answer in the form $(a+bi)$, we write: $61=61+0i$
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