## Elementary Algebra

Published by Cengage Learning

# Chapter 11 - Additional Topics - 11.4 - Complex Numbers - Problem Set 11.4 - Page 493: 41

#### Answer

$-2+23i$

#### Work Step by Step

We multiply each term of the first complex number with the second complex number and then simplify: $(2+3i)(5+4i)$ =$2(5+4i)+3i(5+4i)$ =$10+8i+15i+12i^{2}$ =$10+23i+12i^{2}$ =$10+23i+12(-1)$ [as $i^{2}=-1$] =$10-12+23i$ =$-2+23i$

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