## Elementary Algebra

$-21-12i$
We multiply each term of the first complex number with the second complex number and then simplify: $(-2-3i)(6-3i)$ =$-2(6-3i)-3i(6-3i)$ =$-12+6i-18i+9i^{2}$ =$-12-12i+9(-1)$ [We substitute -1 in place of $i^{2}$ as $i^{2}=-1$] =$-12-9-12i$ =$-21-12i$