Elementary Algebra

{$\frac{1}{2}$}
Using the rules for the factoring of trinomials, we obtain: $4x^{2}-4x+1=0$ $4x^{2}-2x-2x+1=0$ $2x(2x-1)-1(2x-1)=0$ $(2x-1)(2x-1)=0$ $(2x-1)=0$ and $(2x-1)=0$ $x=\frac{1}{2}$ and $x=\frac{1}{2}$ Therefore, the solution set is {$\frac{1}{2}$}.