Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Review Problem Set: 8

Answer

{$\frac{1}{2}$}

Work Step by Step

Using the rules for the factoring of trinomials, we obtain: $4x^{2}-4x+1=0$ $4x^{2}-2x-2x+1=0$ $2x(2x-1)-1(2x-1)=0$ $(2x-1)(2x-1)=0$ $(2x-1)=0$ and $(2x-1)=0$ $x=\frac{1}{2}$ and $x=\frac{1}{2}$ Therefore, the solution set is {$\frac{1}{2}$}.
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