Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Review Problem Set: 3

Answer

{$\frac{2}{7},\frac{1}{3}$}

Work Step by Step

Using the rules for the factoring of trinomials, we obtain: $21x^{2}-13x+2=0$ $21x^{2}-6x-7x+2=0$ $3x(7x-2)-1(7x-2)=0$ $(7x-2)(3x-1)=0$ $(7x-2)=0$ and $(3x-1)=0$ $7x=2$ and $3x=1$ $x=\frac{2}{7}$ and $x=\frac{1}{3}$ Therefore, the solution set is {$\frac{2}{7},\frac{1}{3}$}.
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