Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Review Problem Set - Page 467: 3



Work Step by Step

Using the rules for the factoring of trinomials, we obtain: $21x^{2}-13x+2=0$ $21x^{2}-6x-7x+2=0$ $3x(7x-2)-1(7x-2)=0$ $(7x-2)(3x-1)=0$ $(7x-2)=0$ and $(3x-1)=0$ $7x=2$ and $3x=1$ $x=\frac{2}{7}$ and $x=\frac{1}{3}$ Therefore, the solution set is {$\frac{2}{7},\frac{1}{3}$}.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.