#### Answer

{$0,17$}

#### Work Step by Step

We rearrange the equation into the standard form of a quadratic equation and factor out $x$. We then equate both the factors to zero and solve the equation:
$x^{2}=17x$
$x^{2}-17x+0=0$
$x^{2}-17x=0$
$x(x-17)=0$
$x=0$ and $(x-17)=0$
$x=0$ and $x=17$
Therefore, the solution set is {$0,17$}.