Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Review Problem Set - Page 467: 6



Work Step by Step

Using the rules for the factoring of trinomials, we obtain: $n^{2}-26n+165=0$ $n^{2}-11n-15n+165=0$ $n(n-11)-15(n-11)=0$ $(n-11)(n-15)=0$ $(n-11)=0$ and $(n-15)=0$ $n=11$ and $n=15$ Therefore, the solution set is {$11,15$}.
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