Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Review Problem Set: 1

Answer

{$-6,-1$}

Work Step by Step

Using Property 10.1, which says that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: Step 1: $(2x+7)^{2}=25$ Step 2: $2x+7=\pm \sqrt {25}$ Step 3: $2x+7=\pm 5$ Step 4: $2x+7=5$ or $2x+7=-5$ Step 5: $2x=5-7$ or $2x=-5-7$ Step 6: $2x=-2$ or $2x=-12$ Step 7: $x=-1$ or $x=-6$ The solution set is {$-6,-1$}.
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