# Chapter 10 - Quadratic Equations - Chapter 10 Review Problem Set: 10

{$-5,-1$}

#### Work Step by Step

Using the rules for factoring trinomials, we obtain: $3x^{2}+18x+15=0$ $3x^{2}+3x+15x+15=0$ $3x(x+1)+15(x+1)=0$ $(x+1)(3x+15)=0$ $(x+1)=0$ or $(3x+15)=0$ $x=-1$ or $x=-\frac{15}{3}=-5$ Therefore, the solution set is {$-5,-1$}.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.