Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Review Problem Set - Page 467: 10



Work Step by Step

Using the rules for factoring trinomials, we obtain: $3x^{2}+18x+15=0$ $3x^{2}+3x+15x+15=0$ $3x(x+1)+15(x+1)=0$ $(x+1)(3x+15)=0$ $(x+1)=0$ or $(3x+15)=0$ $x=-1$ or $x=-\frac{15}{3}=-5$ Therefore, the solution set is {$-5,-1$}.
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