## Elementary Algebra

{$-7,2$}
Factoring the equation and setting the factors equal to zero, we obtain: $2x^{2}+10x-28=0$ $2x^{2}-4x+14x-28=0$ $2x(x-2)+14(x-2)=0$ $(x-2)(2x+14)=0$ $(x-2)=0$ or $(2x+14)=0$ $x=2$ or $x=-\frac{14}{2}$ $x=2$ or $x=-7$ Therefore, the solution set is {$-7,2$}.