Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4: 26

Answer

{$-7,2$}

Work Step by Step

Factoring the equation and setting the factors equal to zero, we obtain: $2x^{2}+10x-28=0$ $2x^{2}-4x+14x-28=0$ $2x(x-2)+14(x-2)=0$ $(x-2)(2x+14)=0$ $(x-2)=0$ or $(2x+14)=0$ $x=2$ or $x=-\frac{14}{2}$ $x=2$ or $x=-7$ Therefore, the solution set is {$-7,2$}.
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