Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4 - Page 458: 38



Work Step by Step

Factoring the equation and setting the factors equal to zero, we obtain: $x^{2}-33x+266=0$ $x^{2}-14x-19x+266=0$ $x(x-14)-19(x-14)=0$ $(x-14)(x-19)=0$ $(x-14)=0$ or $(x-19)=0$ $x=14$ or $x=19$ Therefore, the solution set is {$14,19$}.
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