Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4: 36

Answer

{$1,9$}

Work Step by Step

Factoring the equation and setting the factors equal to zero, we obtain: $t^{2}-10t+25=16$ $t^{2}-10t+25-16=0$ $t^{2}-10t+9=0$ $t^{2}-1t-9t+9=0$ $t(t-1)-9(t-1)=0$ $(t-1)(t-9)=0$ $(t-1)=0$ or $(t-9)=0$ $t=1$ or $t=9$ Therefore, the solution set is {$1,9$}.
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