Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4 - Page 458: 37



Work Step by Step

Factoring the equation and setting the factors equal to zero, we obtain: $x^{2}-28x+187=0$ $x^{2}-11x-17x+187=0$ $x(x-11)-17(x-11)=0$ $(x-11)(x-17)=0$ $(x-11)=0$ or $(x-17)=0$ $x=11$ or $x=17$ Therefore, the solution set is {$11,17$}.
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