## Elementary Algebra

Step 1: Comparing $2x^{2}-3x+7=0$ to the standard form of a quadratic equation, $ax^{2}+bx+c=0$, we find: $a=2$, $b=-3$ and $c=7$ Step 2: The quadratic formula is: $x=\frac{-b \pm \sqrt {b^{2}-4ac}}{2a}$ Step 3: Substituting the values of a, b and c in the formula: $x=\frac{-(-3) \pm \sqrt {(-3)^{2}-4(2)(7)}}{2(2)}$ Step 4: $x=\frac{3 \pm \sqrt {9-56}}{4}$ Step 5: $x=\frac{3 \pm \sqrt {-47}}{4}$ The square root of -47 is not a real number, so there are no real number solutions.