Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4 - Page 457: 25



Work Step by Step

Factoring the equation and setting the factors equal to zero, we obtain: $3x^{2}-9x-12=0$ $3x^{2}+3x-12x-12=0$ $3x(x+1)-12(x+1)=0$ $(x+1)(3x-12)=0$ $(x+1)=0$ or $(3x-12)=0$ $x=-1$ or $x=\frac{12}{3}$ $x=-1$ or $x=4$ Therefore, the solution set is {$-1,4$}.
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