Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4: 17

Answer

{$-\frac{1}{5},-\frac{5}{3}$}

Work Step by Step

Factoring the equation and setting the factors equal to zero, we obtain: $15x^{2}+28x+5=0$ $15x^{2}+3x+25x+5=0$ $3x(5x+1)+5(5x+1)=0$ $(5x+1)(3x+5)=0$ $(5x+1)=0$ or $(3x+5)=0$ $x=-\frac{1}{5}$ or $x=-\frac{5}{3}$ Therefore, the solution set is {$-\frac{1}{5},-\frac{5}{3}$}.
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