Answer
{$-\frac{1}{5},-\frac{5}{3}$}
Work Step by Step
Factoring the equation and setting the factors equal to zero, we obtain:
$15x^{2}+28x+5=0$
$15x^{2}+3x+25x+5=0$
$3x(5x+1)+5(5x+1)=0$
$(5x+1)(3x+5)=0$
$(5x+1)=0$ or $(3x+5)=0$
$x=-\frac{1}{5}$ or $x=-\frac{5}{3}$
Therefore, the solution set is {$-\frac{1}{5},-\frac{5}{3}$}.
