Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4 - Page 457: 10



Work Step by Step

Factoring the equation and setting the factors equal to zero, we obtain: $4x^{2}+36x+81=0$ $4x^{2}+18x+18x+81=0$ $2x(2x+9)+9(2x+9)=0$ $(2x+9)(2x+9)=0$ $(2x+9)=0$ or $(2x+9)=0$ $x=-\frac{9}{2}$ or $x=-\frac{9}{2}$ Therefore, the solution set is {$-\frac{9}{2}$}.
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