Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4 - Page 457: 2



Work Step by Step

Factoring the equation and setting the factors equal to zero, we obtain: $x^{2}+4x=60$ $x^{2}+4x-60=0$ $x^{2}-6x+10x-60=0$ $x(x-6)+10(x-6)=0$ $(x-6)(x+10)=0$ $(x-6)=0$ or $(x+10)=0$ $x=6$ or $x=-10$ Therefore, the solution set is {$-10,6$}.
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