Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.4 - Solving Quadratic Equations - Which Method? - Problem Set 10.4 - Page 457: 9



Work Step by Step

Factoring the equation and setting the factors equal to zero, we obtain: $9x^{2}-6x+1=0$ $9x^{2}-3x-3x+1=0$ $3x(3x-1)-1(3x-1)=0$ $(3x-1)(3x-1)=0$ $(3x-1)=0$ or $(3x-1)=0$ $x=\frac{1}{3}$ or $x=\frac{1}{3}$ Therefore, the solution set is {$\frac{1}{3}$}.
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