Answer
See below
Work Step by Step
Assume $A$ be the matrix $m\times n$ and $b \in R^m$ be the fixed nonzero vector in $S$
We can write set $S$ as $S=\{(x \in R^n: Ax=b\}$
Since $b \ne 0$ and $0 \ne S$, $S$ is not a subspace of $R^n$
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