Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 3 - Determinants - 3.1 The Definition of the Determinant - Problems - Page 208: 53

Answer

See below

Work Step by Step

Given $B=\begin{bmatrix} 1 & 4 & -7 & 0 & 0\\ 0 & 0 & 1 & -1 & 0\\-2 & 1 & 3 & -3 & 0 \\0 & 2 & 2 & 4 & 0\\ 0 & 0 & 0 & 0 & -3 \end{bmatrix}$ then $\det (B)=-3.\det (A)\\=\begin{bmatrix} 1 & 4 & -7 & 0 \\ 0 & 0 & 1 & -1 \\-2 & 1 & 3 & -3 \\0 & 2 & 2 & 4 \\ 0 & 0 & 0 & 0 \end{bmatrix}\\ =-3[(1.0.3.4)-1.(1.1.1.4)-1(1.0.(-3).2)-1.(4.0.3.4)+(4.1.(-2).4)-1.((-7).0.1.4)-1.((-7).0.(-2).4)-1(1.(-1).3.2)-1(0.0.3.0)+(4.0.(-3).2)+((-7).(-1).(-2).2)+(0.1.1.0)-1.(4.1.(-3).0)+(1.1.(-3).2)-1(0.0.1.2)+(1.(-1).1.2)+(4.(-1).3.0)-1.((-7).0.(-3).2)+(0.0.3.2)-1(4.(-1).(-2).2)+((-7).0.(-3).0)-1.((-7).(-1).1.0)+(0.0.(-2).2)-1.(0.1.(-2).2)\\ =-3.(-82)\\ =246$
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