Answer
$ \dfrac{ 2! e^{-2 s}}{s^3}$
Work Step by Step
We are given that $f(t)= (t-2)^2 u_{2} (t)$
Now,$F(s)=L[(t-2)^2 u_{2} (t)] \\= e^{-2 s} L [t^2]= \dfrac{ 2! e^{-2 s}}{s^3}$
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