Answer
$$\dfrac{e^{-s}}{s^2}$$
Work Step by Step
We are given that $f(t)=u_1(t) (t-1)$
$L[f(t)]=L u_1(t) (t-1) $
Therefore, $F(s)= e^{-s} \dfrac{1}{s^2}\\=\dfrac{e^{-s}}{s^2}$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 10 - The Laplace Transform and Some Elementary Applications - 10.7 The Second Shifting Theorem - Problems - Page 704: 2
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