Answer
See below
Work Step by Step
We are given that $f(t)=e^{a(t-c)}\cos b 3 (t -c)u_{c} (t)$
Now,$F(s)= L[e^{a(t-c)}\cos b 3 (t -c)u_{c} (t)]\\
=e^{-cs}L[e^{at} \cos bt]\\
= \dfrac{e^{-s}(s-a)}{(s-a)^2+b^2}$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 10 - The Laplace Transform and Some Elementary Applications - 10.7 The Second Shifting Theorem - Problems - Page 704: 11
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