Answer
$$\dfrac{e^{-2s}}{s-3}$$
Work Step by Step
We are given that $f(t)=e^{3(t-2)} u_2(t)$
Now,$F(s)=L[ e^{3(t-2)} u_2(t)] \\=e^{-2s}L e^{3t}\\= \dfrac{e^{-2s}}{s-3}$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 10 - The Laplace Transform and Some Elementary Applications - 10.7 The Second Shifting Theorem - Problems - Page 704: 3
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