Answer
$\frac{2}{s^3(s-1)}$
Work Step by Step
Given: $f(t)=\int^t_0 (t-\omega)^2\cos 2\omega d\omega$
Using the Convolution Theorem
$L[f(s)]=L[f*g]\\
=L[f].L(g)\\
=L[t^2].L[\cos 2t]\\
=\frac{2}{s^3}.\frac{1}{s-1}\\
=\frac{2}{s^3(s-1)}$
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