Answer
$(u-v^2)(u^2+v^3+v^4)$
Work Step by Step
RECALL:
$A^3-B^3=(A+B)(A^2+AB+B^2)$
The given binomial can be written as:
$=u^3-(v^2)^3$
The binomial above is a difference of two cubes.
Factor using the the formula above with $A=u$ and $B=v^2$ to obtain:
$=(u-v^2)[u^2+(u)(v^2) +(v^2)^2]
\\=(u-v^2)(u^2+uv^2+v^4)$
