College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 40

Answer

$(y-4)(y^2+4y+16)$

Work Step by Step

RECALL: $A^3-B^3=(A-B)(A^2+AB+B^2)$ The given binomial can be written as: $y^3-4^3$ The binomial above is a difference of two cubes. Factor using the the formula above with $A=y$ and $B=4$ to obtain: $=(y-4)(y^2+y(4) + 4^2) \\=(y-4)(y^2+4y+16)$
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