College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 36

Answer

$(4a+3)^2$

Work Step by Step

RECALL: $A^2+2AB+B^2=(A+B)^2$ The given trinomial can be written as: $=(4a)^2+2(4a)(3) + 3^2$ The expression above is a perfect square trinomial with $A=4a$ and $B=3$ Factor using the formula above to obtain: $=(4a+3)^2$
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