## College Algebra 7th Edition

$(4a+3)^2$
RECALL: $A^2+2AB+B^2=(A+B)^2$ The given trinomial can be written as: $=(4a)^2+2(4a)(3) + 3^2$ The expression above is a perfect square trinomial with $A=4a$ and $B=3$ Factor using the formula above to obtain: $=(4a+3)^2$