College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 44

Answer

$(1+10y)(1-10y+100y^2)$

Work Step by Step

RECALL: $A^3+B^3=(A+B)(A^2-AB+B^2)$ The given binomial can be written as: $=1^3+10^3y^3 \\=1^3+(10y)^3$ The binomial above is a sum of two cubes. Factor using the the formula above with $A=1$ and $B=10y$ to obtain: $=(1+10y)[1^2-(1)(10y) +(10y)^2] \\=(1+10y)(1-10y+100y^2)$
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