## College Algebra 7th Edition

Published by Brooks Cole

# Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 42: 29

#### Answer

$(x-y+3)(x+y+3)$

#### Work Step by Step

RECALL: $A^2-B^2=(A-B)(A+B)$ Factor the difference of two squares using the formula above with $A=x+3$ and $B=y$ to obtain: $=[(x+3)-y][(x+3)+y] \\=(x+3-y)(x+3+y) \\=(x-y+3)(x+y+3)$

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