College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 28

Answer

$x^2$

Work Step by Step

The given radical can be written as: $=\sqrt[5]{(x^2)^5}$ RECALL: (i) $\sqrt[n]{a^n} = |a|$ when $n$ is even (ii) $\sqrt[n]{a^n} = a$ when $n$ is odd The given radical has n=5, which is even. Use rule (ii) above, where $a=x^2$, to obtain: $\sqrt[5]{(x^2)^5}=x^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.