Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 29: 25

(a) 6 (b) 4 (c) 1/4

(a) $\frac{\sqrt{216}}{\sqrt{6}}=\sqrt{\frac{216}{6}}=\sqrt{36}=6$ (b) $\sqrt[3]{2}\sqrt[3]{32}=\sqrt[3]{64}=4$ (c) $\displaystyle \sqrt[4]{\frac{1}{4}}\sqrt[4]{\frac{1}{64}}=\sqrt[4]{\frac{1}{256}}=\frac{1}{\sqrt[4]{256}}=\frac{1}{4}$