Answer
(a) 1/2
(b) 2
(c) 1/3
Work Step by Step
(a) $\sqrt[5]{\frac{1}{8}}\sqrt[5]{\frac{1}{4}}=\sqrt[5]{\frac{1}{8*4}}=\sqrt[5]{\frac{1}{32}}=\frac{1}{2}$
(b) $\sqrt[6]{\frac{1}{2}}\sqrt[6]{128}=\sqrt[6]{64}=2$
(c) $\displaystyle \frac{\sqrt[3]{4}}{\sqrt[3]{108}}=\sqrt[3]{\frac{4}{108}}=\sqrt[3]{\frac{1}{27}}=\frac{1}{\sqrt[3]{27}}=\frac{1}{3}$
