Answer
(a) 8
(b) -4
(c) -2
Work Step by Step
(a) $\sqrt{64}=\sqrt{8^{2}}=8$
(b) $\sqrt[3]{-64}=\sqrt[3]{(-4)^{3}}=-4$
(c) $\sqrt[5]{-32}=\sqrt[5]{(-2)^{5}}=-2$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 29: 20
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