Answer
(a) 4
(b) 2
(c) 1/2
Work Step by Step
(a) $\sqrt{16}=\sqrt{4^2}=4$
(b) $\sqrt[4]{16}=\sqrt[4]{2^{4}}=2$
(c) $\displaystyle \sqrt[4]{\frac{1}{16}}=\sqrt[4]{(\frac{1}{2})^{4}}=\frac{1}{2}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 29: 19
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