#### Answer

$(-2, 3)$
Refer to the image below for the graph.

#### Work Step by Step

First step is to find the zeros of each factor.
The factors $x+2$ and $x-3$ are zero when $x=-2$ and $x=3$, respectively.
Next step is to find the intervals.
The zeros $-2$ and $3$ divide the number line into three intervals, namely:
$(-\infty, -2), (-2, 3), \text{ and } (3, +\infty)$.
$\bf\text{Make a table of signs}.$
(refer to the attached image below)
$\bf\text{Solve}$
From the table of signs, it can be seen that $(x+2)(x-3)\lt 0$ in the interval $(-2, 3)$.
The inequality involves $lt$ therefore the endpoints $-$ and $3$ are not part of the solution set.
Thus, the solution set is $(-2, 3)$.
To graph this, plot holes at $-2$ and $3$ then shade the region between them.
(refer to the attached image in the answer part above)