#### Answer

$(-\infty, -1]$
Refer to the image below for the graph.

#### Work Step by Step

Distribute $-1$ on the right side of the inequality to obtain:
$4-3x \le -1-8x$
Add $8x$ and subtract $4$to both sides of the inequality to obtain:
$\begin{array}{ccc}
&4-3x+8x -4&\le & -1-8x+8x-4
\\&5x &\le &-5
\end{array}$
Divide $5$ to both sides of the inequality to obtain:
$\begin{array}{ccc}
\\&\dfrac{5x}{5} &\le & \dfrac{-5}{5}
\\&x &\le &-1
\end{array}$
Thus, the solution set is $(-\infty, -1]$.
To graph this solution set, plot a solid dot at $-1$ then shade the region to its left.
(refer to the attached image in the answer part above for the graph)