#### Answer

$(-\infty, 11]$
Refer to the image below for the graph.

#### Work Step by Step

Distribute $2$ on the left side of the inequality to obtain:
$14x-6 \le 12x+16$
Subtract $12x$ and add $6$to both sides of the inequality to obtain:
$\begin{array}{ccc}
&14x-6-12x+6 &\le &12x+16-12x+6
\\&2x &\le &22
\end{array}$
Divide $2$ to both sides of the inequality to obtain:
$\begin{array}{ccc}
\\&\dfrac{2x}{2} &\le & \dfrac{22}{2}
\\&x &\le &11
\end{array}$
Thus, the solution set is $(-\infty, 11]$.
To graph this solution set, plot a solid dot at $11$ then shade the region to its left.
(refer to the attached image in the answer part above for the graph)