College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.7 - Solving Inequalities - 1.7 Exercises - Page 148: 31

Answer

$(2.5, 5.5]$ Refer to the image below for the graph.

Work Step by Step

Multiply $12$ to each part of the inequality to eliminate the fractions: $\begin{array}{ccccc} &12\left(\dfrac{2}{3}\right) &\ge &12\left(\dfrac{2x-3}{12}\right) &\gt &12\left(\dfrac{1}{6}\right) \\&8 &\ge &2x-3 &\gt &2 \end{array}$ Add $3$ to each part of the inequality to obtain: $\begin{array}{ccccc} &8+3 &\ge &2x-3+3 & \gt &2+3 \\&11 &\ge &2x &\gt &5 \end{array}$ Divide each part by $2$ to obtain: $\begin{array}{ccccc} &\dfrac{11}{2} &\ge &\dfrac{2x}{2} &\gt &\dfrac{5}{2} \\&5.5 &\ge &x &\gt &2.5 \end{array}$ This inequality is equivalent to: $2.5 \lt x \le 5.5$ Thus, the solution set is $\bf(2.5 , 5.5]$. To graph this solution set, a hole (hollow dot) at $2.5$ and a solid dot at $5.5$ then shade the region in between. (refer to the attached image in the answer part above for the graph)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.