## College Algebra 7th Edition

$(-\infty, -\frac{1}{2}]$ Refer to the image below for the graph.
Add $9x$ on both sides to obtain: $5+6x \le 2$ Subtract $5$ on both sides to obtain: $6x \le -3$ Divide by $6$ on both sides to obtain: $x \le \dfrac{-3}{6} \\x \le -\dfrac{1}{2}$ The solution set is the set of real numbers less than or equal to $-\dfrac{1}{2}$. In interval notation, the solution set is: $(-\infty, -\frac{1}{2}]$ To graph this inequality, plot a solid dot at $x=-\dfrac{1}{2}$ then shade the region to its left. (refer to the attached image in the answer part)