#### Answer

$x=0$ or $x=\pm\sqrt{5}$

#### Work Step by Step

We solve by factoring:
$x^{5}=5x^{3}$
$x^{5}-5x^{3}=0$
$x^{3}(x^{2}-5)=0$
$x^{3}(x-\sqrt{5})(x+\sqrt{5})=0$
$x^3=0$ or $x-\sqrt{5}=0$ or $x+\sqrt{5}=0$
$x=0$ or $x=\pm\sqrt{5}$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=0$ or $x=\pm\sqrt{5}$

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