#### Answer

$x=0$ or $x=2$ or $x=3$

#### Work Step by Step

We solve by factoring:
$x^{3}-5x^{2}+6x=0$
$x(x^{2}-5x+6)=0$
$x(x-2)(x-3)=0$
$x=0$ or $x-2=0$ or $x-3=0$
$x=0$ or $x=2$ or $x=3$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=0$ or $x=2$ or $x=3$

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